From 2648c1deb2be1f3c827c94790c1c5e00130e40a1 Mon Sep 17 00:00:00 2001 From: Francesco Rizzi Date: Thu, 29 Jun 2023 16:27:21 +0200 Subject: [PATCH] fix typos in doc #123 --- docs/source/apicpp.rst | 2 +- docs/source/apipy.rst | 2 +- 2 files changed, 2 insertions(+), 2 deletions(-) diff --git a/docs/source/apicpp.rst b/docs/source/apicpp.rst index 5d3ff231..ff901c36 100644 --- a/docs/source/apicpp.rst +++ b/docs/source/apicpp.rst @@ -96,7 +96,7 @@ A *pressio-demoapps* C++ problem class meets the following API Returns the total number of degrees of freedom on the **stencil** mesh. Note that, in general, this is not the same as the number of stencil mesh cells. When you have multiple dofs/cell (for example Euler equations), - then the total # of dofs on stencil mesh = # dofs/cell times the # of sample mesh cells. + then the total # of dofs on stencil mesh = # dofs/cell times the # of stencil mesh cells. .. _Supported Backends And Types: diff --git a/docs/source/apipy.rst b/docs/source/apipy.rst index b8085111..8e498719 100644 --- a/docs/source/apipy.rst +++ b/docs/source/apipy.rst @@ -66,7 +66,7 @@ Problem Class Returns the total number of degrees of freedom on the **stencil** mesh. Note that, in general, this is not the same as the number of stencil mesh cells. When you have multiple dofs/cell (for example Euler equations), - then the total # of dofs on stencil mesh = # dofs/cell times the # of sample mesh cells. + then the total # of dofs on stencil mesh = # dofs/cell times the # of stencil mesh cells. :rtype: int